Y=-16x^2+79x+6

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Solution for Y=-16x^2+79x+6 equation:



=-16Y^2+79Y+6
We move all terms to the left:
-(-16Y^2+79Y+6)=0
We get rid of parentheses
16Y^2-79Y-6=0
a = 16; b = -79; c = -6;
Δ = b2-4ac
Δ = -792-4·16·(-6)
Δ = 6625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{6625}=\sqrt{25*265}=\sqrt{25}*\sqrt{265}=5\sqrt{265}$
$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-79)-5\sqrt{265}}{2*16}=\frac{79-5\sqrt{265}}{32} $
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-79)+5\sqrt{265}}{2*16}=\frac{79+5\sqrt{265}}{32} $

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